2. Sample Papers
  3. JEE Main & Advanced

JEE Main & Advanced Sample Paper JEE Main - Mock Test - 9

  • question_answer
    In the reaction \[A\to \] Products, when the concentration of A was reduced from \[2.4\times {{10}^{-2}}M\]to \[1.2\times {{10}^{-2}}M\]the rate decreased 8 times at the same temperature. The reaction is

    A) zero order     

    B) first order

    C) second order   

    D) third order.

    Correct Answer: D

    Solution :

    [d]:\[\frac{{{r}_{1}}}{{{r}_{2}}}={{\left[ \frac{2.4\times {{10}^{-2}}}{1.2\times {{10}^{-2}}} \right]}^{x}}\] \[8={{(2)}^{x}}\Rightarrow {{(2)}^{3}}={{(2)}^{x}}\therefore x=3\] Hence, the order of reaction is 3.


You need to login to perform this action.
You will be redirected in 3 sec spinner