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JEE Main & Advanced Sample Paper JEE Main - Mock Test - 9

  • question_answer
    When a brown compound of Mn  is treated with HCl, it gives a gas (B). The gas (B) taken in excess reacts with \[N{{H}_{3}}\] to give an explosive compound (C). The compounds A, B and C are

    A) \[A=Mn{{O}_{2}}, B=C{{l}_{2}},C=NC{{l}_{3}}\]

    B) \[A=MnO,B=C{{l}_{2}},C=N{{H}_{3}}Cl\]

    C) \[A=M{{n}_{3}}{{O}_{4}},B=C{{l}_{2}},C=NC{{l}_{3}}\]

    D) \[A=Mn{{O}_{3}},B=C{{l}_{2}},C=NC{{l}_{2}}\]

    Correct Answer: A

    Solution :

    [a]:\[\underset{(A)}{\mathop{Mn{{O}_{2}}}}\,+4HCl\xrightarrow[{}]{{}}\underset{(B)}{\mathop{C{{l}_{2}}}}\,+MnC{{l}_{2}}+2{{H}_{2}}O\] \[\underset{(Excess)}{\mathop{3Cl}}\,+N{{H}_{3}}\xrightarrow[{}]{{}}\underset{(C)}{\mathop{NC{{l}_{3}}}}\,+3HCl\]


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