A) 8
B) 10
C) 12
D) 14
Correct Answer: A
Solution :
At \[t=0,\]current will flow only in \[12\Omega \] resistance |
\[\therefore \,\,{{I}_{\min }}=\frac{5}{12}\] |
At \[t\to \infty \] both \[{{L}_{1}}\]and \[_{2}\] behave as conducting wires |
\[\therefore \,\,{{R}_{eff}}=\frac{3}{2},\,\,{{I}_{\max }}=\frac{10}{3}\] |
\[\frac{{{I}_{\max }}}{{{I}_{\min }}}=8\] |
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