A) \[-10\]
B) \[-8\]
C) \[7\]
D) \[9\]
Correct Answer: B
Solution :
[b] Applying \[{{C}_{3}}\to {{C}_{3}}-2{{C}_{1}}-2{{C}_{2}},\] we get \[=(\alpha +\beta +\gamma )({{\alpha }^{2}}+{{\beta }^{2}}+{{\gamma }^{2}}-\alpha \beta -\beta \gamma -\gamma \alpha )\] \[=(\alpha +\beta +\gamma )({{(\alpha +\beta +\gamma )}^{2}}-3(\alpha \beta +\beta \gamma +\gamma \alpha ))\] \[=1\times ({{1}^{2}}-3\times (3))\] \[=-8\]You need to login to perform this action.
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