A) \[\frac{3}{4}\]
B) \[\frac{3}{2}\]
C) \[\frac{3}{8}\]
D) \[3\]
Correct Answer: B
Solution :
[b] Required area \[=2\int\limits_{0}^{1}{\left[ (2-x)-{{x}^{1/3}} \right]}dx\] \[=2\left[ 2x-\frac{{{x}^{2}}}{2}-\frac{3{{x}^{4/3}}}{4} \right]_{0}^{1}=2\left[ 2-\frac{1}{2}-\frac{3}{4} \right]=\frac{3}{2}\]You need to login to perform this action.
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