A) \[12.42\times {{10}^{-21}}J\],968 m/s
B) \[6.21\times {{10}^{-21}}J\], 968 m/s
C) \[8.78\times {{10}^{-21}}J\], 684 m/s
D) \[12.42\times {{10}^{-21}}J\], 684 m/s
Correct Answer: D
Solution :
As \[KE=\frac{3}{2}kT\]and\[{{v}_{rms}}=\sqrt{\frac{3RT}{M}}\] \[\therefore \]\[K{{E}_{2}}=2K{{E}_{1}}=2\times 6.21\times {{10}^{-21}}\] \[=12.42\times {{10}^{-12}}J\] \[\frac{{{v}_{rms,2}}}{{{v}_{rms,1}}}=\sqrt{\frac{{{T}_{2}}}{{{T}_{1}}}}=\sqrt{2}\] \[\therefore \]\[{{v}_{rms,2}}=\sqrt{2}\times {{v}_{rms,1}}=684m/s\]
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