A) 140 kJ/mol
B) 240 kJ/mol
C) 370 kJ/mol
D) 30 kJ/mol
Correct Answer: A
Solution :
Idea Problem includes concept of Arrhenius equation for different rate ?constant of a common reaction. To solve this problem student is advised to write the Arrhenius equation for every rate constant. Then, put the value in\[k=\left( \frac{{{k}_{1}}{{k}_{2}}}{{{k}_{3}}} \right)2/3\]to get the value of\[{{E}_{a}}\] Putting\[k=A{{e}^{-{{E}_{a}}IRT}}\] \[{{k}_{1}}=A{{e}^{\frac{-{{E}_{a1}}}{RT}}},{{k}_{2}}=A{{e}^{-\frac{{{E}_{{{a}_{2}}}}}{RT}}}\] \[{{K}_{3}}=A{{e}^{-\frac{{{E}_{{{a}_{3}}}}}{RT}}}\] \[k={{\left( \frac{A{{e}^{-\frac{{{E}_{{{a}_{1}}}}}{RT}}}\cdot A{{e}^{-\frac{{{E}_{a}}_{_{2}}}{RT}}}}{A{{e}^{-{{E}_{{{a}_{3}}}}/RT}}} \right)}^{2/3}}=A{{e}^{-{{E}_{a}}/RT}}\] \[{{E}_{a}}=\frac{2}{3}[{{E}_{{{a}_{1}}}}+{{E}_{{{a}_{2}}}}-{{E}_{{{a}_{3}}}}]\] \[{{E}_{a}}=\frac{2}{3}[200+90-80]=\frac{2}{3}[210]\] = 140 kJ/mol TEST Edge Students are advised to study the concept of Arrhenius equation at different temperatures. Since, these types of questions are also asked.You need to login to perform this action.
You will be redirected in
3 sec