A) (2, 14)
B) (12,18)
C) (2, 4)
D) (4, 2)
Correct Answer: C
Solution :
Here, the minimum distance occur along the common normal. Any normal to y2 = 8 x at\[(2{{t}^{2}},4t)\]is\[tx+y=4t+2{{t}^{3}}\] It passes through the centre (0, 6) of the circle \[6=4t+2{{t}^{3}}\Rightarrow t=1\]So, required points (2, 4).You need to login to perform this action.
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