A) 120 mA
B) 40 mA
C) 80 mA
D) 60 mA
Correct Answer: B
Solution :
Potential difference induced in both the rods would have different polarity. PD (potential difference) in \[ab=B/v=1\times 0.1m\times 4m/s=0.4V\] PD (potential difference) in \[cd=B/v=1\times 0.1m\times 2m/s=0.2V\] So, the arrangement would act like \[\therefore \]Current\[l=\frac{0.4-0.2}{5}=\frac{0.2}{5}=0.04A=40mA\]You need to login to perform this action.
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