A) \[\frac{x-1}{-3}=\frac{y+2}{5}=\frac{z-3}{4}\]
B) \[\frac{x-1}{1}=\frac{y+2}{-1}=\frac{z-3}{2}\]
C) \[\frac{x+2}{-3}=\frac{y-3}{5}=\frac{z+3}{4}\]
D) None of these
Correct Answer: A
Solution :
If l, m, n be the direction cosines of the line, then as it lies in both the given planes it is perpendicular to their normal i.e., \[l-m+2n=0\]and\[3l+m+n=0\]or\[\frac{l}{-3}=\frac{m}{5}=\frac{n}{4}\]So, equation of the line is \[\frac{x-1}{-3}=\frac{y+2}{5}=\frac{z-3}{4}\]
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