A) \[\frac{-q}{1+\sqrt{2}}\]
B) \[\frac{-2q}{2+\sqrt{2}}\]
C) \[-2q\]
D) \[+q\]
Correct Answer: B
Solution :
Here we have\[\frac{Qq}{a}+\frac{{{q}^{2}}}{a}+\frac{Qq}{a\sqrt{2}}=0\] or\[Q\sqrt{2}+q\sqrt{2}+Q=0\]or\[Q(\sqrt{2}+1)=-q\sqrt{2}\] \[\therefore \]\[Q=-\frac{q\sqrt{2}}{\sqrt{2}+1}=-\frac{2q}{2+\sqrt{2}}\]You need to login to perform this action.
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