A) mg
B) mg/2
C) \[\text{mg/}\sqrt{\text{3}}\]
D) 2mg
Correct Answer: C
Solution :
\[mg=T\cos {{30}^{o}}\] \[N=T\sin {{30}^{o}}\] \[\Rightarrow N=\frac{mg}{\sqrt{3}}\]You need to login to perform this action.
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