A) \[x{{e}^{\sin x}}-{{e}^{\sin x}}\sec x+C\]
B) \[x{{e}^{\cos x}}-{{e}^{\sin x}}\sec x+C\]
C) \[{{x}^{2}}{{e}^{\sin x}}+{{e}^{\sin x}}\sec x+C\]
D) \[2x\,{{e}^{\sin x}}-{{e}^{\sin x}}\tan x+C\]
Correct Answer: A
Solution :
\[\int_{{}}^{{}}{{{e}^{\sin x}}}\left( \frac{x{{\cos }^{3}}x-\sin x}{{{\cos }^{2}}x} \right)dx\] \[=\int_{{}}^{{}}{{{e}^{\sin x}}}x\cos xdx-\int_{{}}^{{}}{{{e}^{\sin x}}}\tan x\sec xdx\] \[=\int_{{}}^{{}}{xd}\left( {{e}^{\sin x}} \right)-\int_{{}}^{{}}{{{e}^{\sin x}}}d(\sec x)\] \[=\left\{ x{{e}^{\sin x}}-\int_{{}}^{{}}{{{e}^{\sin x}}}dx \right\}\] \[-\left\{ {{e}^{\sin x}}\sec x-\int_{{}}^{{}}{{{e}^{\sin x}}}\sec x\cos xdx \right\}\] \[=x{{e}^{\sin x}}-{{e}^{\sin x}}\sec x+C\]You need to login to perform this action.
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