A) 15.1
B) 30.2
C) -36.2
D) None of these
Correct Answer: A
Solution :
\[\frac{1}{2}{{N}_{2}}(g)+\frac{1}{2}{{O}_{2}}(g)\xrightarrow[{}]{{}}NO(g);{{\Delta }_{f}}{{H}^{o}}=90.2\] \[{{N}_{2}}(g)+{{O}_{2}}\to 2NO(g);{{\Delta }_{f}}H{}^\circ =90.2\times 2\] ? (1) \[2NO(g)+{{O}_{2}}(g)\xrightarrow[{}]{{}}2N{{O}_{2}}(g);{{\Delta }_{f}}{{H}^{o}}=-114\] ? (2) \[2N{{O}_{2}}(g)\frac{1}{2}{{O}_{2}}(g)\xrightarrow[{}]{{}}{{N}_{2}}{{O}_{5}}(g)\] \[{{\Delta }_{f}}{{H}^{o}}=\frac{-102.6}{2}=-51.3\] ? (3) \[Eq.(1)+(2)+(3)\]\[{{N}_{2}}(g)+\frac{5}{2}{{O}_{2}}(g)\xrightarrow[{}]{{}}{{N}_{2}}{{O}_{5}}(g)\] \[{{\Delta }_{f}}{{H}^{o}}({{N}_{2}}{{O}_{5}},g)=15.1\,\text{kJ/mol}\]You need to login to perform this action.
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