question_answer

\[A\xrightarrow[(ii){{H}^{\oplus }}]{(i)NaOI}B\xrightarrow[{}]{SOC{{l}_{2}}}C\xrightarrow[NaOH]{{{C}_{6}}{{H}_{5}}N{{H}_{2}}}\] \[D\xrightarrow[\begin{smallmatrix}  Conc.{{H}_{2}}S{{O}_{4}} \\  (1\,equivalent) \end{smallmatrix}]{Conc.HN{{O}_{3}}}E(\text{Major})\]E can be-

A)  

B)  

C)  

D)  

Correct Answer: B

Solution :

 \[X-\overset{\begin{smallmatrix}  O \\  || \end{smallmatrix}}{\mathop{C}}\,-C{{H}_{3}}\xrightarrow[{{H}^{\oplus }}]{NaOH}X-\overset{\begin{smallmatrix}  O \\  || \end{smallmatrix}}{\mathop{C}}\,-OH\] \[\xrightarrow[{}]{SOC{{l}_{2}}}X-\overset{\begin{smallmatrix}  O \\  || \end{smallmatrix}}{\mathop{C}}\,-Cl\xrightarrow[{}]{Ph-N{{H}_{2}}}X-\overset{\begin{smallmatrix}  O \\  || \end{smallmatrix}}{\mathop{C}}\,-NH-PH\]