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JEE Main & Advanced Sample Paper JEE Main Sample Paper-11

  • question_answer
    If g is the acceleration due to gravity on the earth's surface, the change in the potential energy of an object of mass m raised from the surface of the earth to a height equal to the radius R of the earth is

    A)  mgR/2                 

    B)  2mgR

    C)  mgR                                     

    D)  -mgR

    Correct Answer: A

    Solution :

     \[{{U}_{g}}=-\frac{G{{M}_{1}}{{M}_{2}}}{R}\] \[\Rightarrow \]\[{{U}_{f}}-{{U}_{i}}=-\frac{GMm}{2R}-\left( -\frac{GMm}{R} \right)\] \[\Delta U=\frac{GMm}{2R}=\frac{mgR}{2}\left\{ g=\frac{GM}{{{R}^{2}}} \right\}\]


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