A) zero
B) 0.02
C) 0.03
D) 0.036.
Correct Answer: B
Solution :
In the circuit, diode \[{{D}_{1}}\] is forward biased, while \[{{D}_{2}}\]reverse biased. Therefore, current i (through \[{{D}_{1}}\] an \[100\,\Omega \]resistance) will be \[i=\frac{6}{50+100+150}=0.02A\] Here, \[50\,\Omega \]is the resistance of \[{{D}_{1}}\] in forward biasing.You need to login to perform this action.
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