A) \[\sqrt{2}\pi \text{Ns}\]
B) \[\sqrt{3}\pi \text{Ns}\]
C) \[2\sqrt{3}\pi \text{Ns}\]
D) \[3\sqrt{2}\pi \text{Ns}\]
Correct Answer: D
Solution :
The angular displacement of the particle in t = 1 sec is \[\theta =\omega t=\frac{v}{R}t=\frac{3\pi }{2}\] \[\therefore \]The magnitude of impulse by centripetal force in t = 1 second = change in momentum \[=\sqrt{2}mv=3\sqrt{2}\pi Ns\]You need to login to perform this action.
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