A) \[[1,2]\]
B) \[[-1,1]\]
C) \[[1,\infty ]\]
D) \[[{{2}^{-1/2}},{{2}^{1/2}}]\]
Correct Answer: B
Solution :
For non-trivial solution. \[\Delta =\left| \begin{matrix} \sqrt{2a} & \sin B & \cos B \\ 1 & \cos B & \sin B \\ -1 & \sin B & -\cos B \\ \end{matrix} \right|-\] \[\Rightarrow \]\[a\sqrt{2}[-{{\cos }^{2}}B-{{\sin }^{2}}B]-\sin B[-\cos B+\sin B]\] \[+\cos B[\sin B+\cos B]=0\] \[\Rightarrow \]\[-a\sqrt{2}+\sin 2B+\cos 2B=0\Rightarrow a\in [-1,1]\]You need to login to perform this action.
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