A)
Induced current side Force on left side Force on right Counterclockwise To the left To the left
B)
Induced current side Force on left side Force on right Counterclockwise To the right To the left
C)
Induced current side Force on left side Force on right Clockwise To the right To the left
D)
Induced current side Force on left side Force on right Clockwise To the right To the right
Correct Answer: D
Solution :
As flux decreases to maintain flux, current in loop is clockwise. Force on DA due to long wire is towards left while on wire BC towards right.You need to login to perform this action.
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