JEE Main & Advanced
Sample Paper
JEE Main Sample Paper-12
question_answer
At very high temperatures vibrational degrees also becomes active. At such temperatures an ideal diatomic gas has a molar specific heat at constant pressure, \[{{C}_{p}}=\]
A) 3R/2
B) 5R/2
C) 6R/2
D) 9R/2
Correct Answer:
D
Solution :
At high temperature for diatomic gas f = 7 \[{{C}_{p}}=\frac{f\,R}{2}+R=\frac{9R}{2}\]