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JEE Main & Advanced Sample Paper JEE Main Sample Paper-12

  • question_answer
    At very high temperatures vibrational degrees also becomes active. At such temperatures an ideal diatomic gas has a molar specific heat at constant pressure, \[{{C}_{p}}=\]

    A)  3R/2                     

    B)  5R/2

    C)  6R/2                     

    D)  9R/2

    Correct Answer: D

    Solution :

     At high temperature for diatomic gas f = 7 \[{{C}_{p}}=\frac{f\,R}{2}+R=\frac{9R}{2}\]


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