A) 0.99%
B) 25%
C) 50%
D) 75%
Correct Answer: C
Solution :
A: blood result says positive about the disease \[{{\text{B}}_{\text{1}}}\]: Person suffers from the disease\[\therefore \]\[P({{B}_{1}})=\frac{1}{100}\] \[{{\text{B}}_{\text{2}}}\]: person does not suffer\[\therefore \]\[P({{B}_{2}})=\frac{99}{100}\] \[P(A/{{B}_{1}})=\frac{99}{100},P(A/{{B}_{2}})=\frac{1}{100}\] \[P({{B}_{1}}/A)=\frac{P({{B}_{1}}).P(A/{{B}_{1}})}{P({{B}_{1}}).P(A/{{B}_{1}})+P({{B}_{2}}).P(A/{{B}_{2}})}\] \[=\frac{\frac{1}{100}.\frac{99}{100}}{\frac{1}{100}.\frac{99}{100}+\frac{99}{100}.\frac{1}{100}}=\frac{99}{2.99}=\frac{1}{2}=50%\]You need to login to perform this action.
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