A) 600K
B) 300K
C) 1200K
D) 1000K
Correct Answer: A
Solution :
Mole of X reacted = 0.75 mole Heat liberated at constant pressure \[=0.75\times 10\,\text{kJ}\] \[=7.5\,\text{kJ}\] Mole of X remaining \[=\frac{1}{4}\]mole Mole of formed \[=\frac{3}{4}\times \frac{2}{3}=\frac{1}{2}\] \[\left( \frac{1}{4}{{C}_{p,m}}_{(X)}+\frac{1}{2}{{C}_{p,m(Y)}} \right)(\Delta T)=q=7500\] \[\Delta T=\frac{7500}{\frac{40}{4}+\frac{30}{2}}=300\] Final temperature \[=300+300=600K\]You need to login to perform this action.
You will be redirected in
3 sec