List-I | List-II |
I \[\text{L}{{\text{i}}_{\text{2}}}\] | A. 3 |
II \[{{\text{N}}_{\text{2}}}\] | B. 1.5 |
III \[\text{B}{{\text{e}}_{\text{2}}}\] | C. 1.0 |
IV \[{{\text{O}}_{\text{2}}}\] | D. 0 |
E. 0 |
A) \[\text{I-B,II-C,III-A,IV-E}\]
B) \[\text{I-C,II-A,III-D,IV-E}\]
C) \[\text{I-D,II-A,III-E,IV-C}\]
D) \[\text{I-C,II-B,III-E,IV-A}\]
Correct Answer: B
Solution :
\[B.O.={\scriptstyle{}^{1}/{}_{2}}[{{N}_{b}}-{{N}_{a}}]\] \[L{{i}_{2}}=\frac{4-2}{2}=1;{{N}_{2}}=3;Be=0,{{O}_{2}}=2.\]You need to login to perform this action.
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