A) 0.4
B) 2.4 h
C) 4.0 h
D) Can't be calculated since rate constant is not given
Correct Answer: C
Solution :
The concentration of A remains 1/4th in 8 hours. Therefore \[\frac{1}{{{2}^{n}}}=\frac{1}{4}n=2\]and \[{{E}_{{\scriptstyle{}^{1}/{}_{2}}}}\]is \[8=n\times {{t}_{{\scriptstyle{}^{1}/{}_{2}}}};{{t}_{{\scriptstyle{}^{1}/{}_{2}}}}=4;\] In 4 hours 0.6 will become 0.3You need to login to perform this action.
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