A) x +7 y = 0
B) x - y = 0
C) x - 7 y = 0
D) both [A] and [B]
Correct Answer: D
Solution :
Centre of the circle is \[\left( \frac{1}{2},\frac{3}{2} \right).\] Its distance from the line \[x+y-1=0\]is\[\sqrt{2}\] Let the required line be mx - y = 0 \[\therefore \]\[\left| \frac{\frac{m}{2}+\frac{3}{2}}{\sqrt{{{m}^{2}}+1}} \right|=\sqrt{2}\Rightarrow m=1,-1/7\] \[\therefore \] The lines are \[x-y=0,x+7y=0\]
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