JEE Main & Advanced Sample Paper JEE Main Sample Paper-13

  • question_answer
    The elastic flux \[\phi \] through a hemisphere surface of radius R, placed in a uniform electric field of intensity E parallel to the axis of its plane is

    A)  \[2\pi RE\]                         

    B)  \[2\pi {{R}^{2}}E\]

    C)  \[\pi {{R}^{2}}E\]                            

    D)  \[\frac{4}{3}\,\pi {{R}^{3}}E\]

    Correct Answer: C

    Solution :

     The electric flux through any surface is equal to the product of electric field intensity at the surface and component of the area vector perpendicular to electric field \[OC{{H}_{3}}\]


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