A) zero
B) \[mga\]
C) \[mga\,\sin \,\theta \]
D) \[\frac{mga\,\,\sin \,\,\theta }{2}\]
Correct Answer: D
Solution :
Because the cubical block slides with a uniform velocity and does not topple. Hence, torque produced by weight = torque due to normal force on the blockYou need to login to perform this action.
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