A) \[{{30}^{o}}\]
B) \[{{45}^{o}}\]
C) \[{{60}^{o}}\]
D) \[{{90}^{o}}\]
Correct Answer: B
Solution :
Applying law of conservation of momentum along two axes of plane of motion, we get: \[{{V}_{3}}\] i.e.\[,\] \[MgC{{l}_{2}}\to 2NaOH\to Mg{{(OH)}_{2}}\downarrow +2NaCl\] ? (i) Also, \[Mg{{(OH)}_{2}}\] \[M{{g}^{2+}}\] \[O{{H}^{-}}\] \ \[{{K}_{sp}}\] According to law of conservation of KE \[Mg{{(OH)}_{2}}\] \[Mg{{(OH)}_{2}}\,\underset{s}{\mathop{M{{g}^{2+}}}}\,+\underset{2s}{\mathop{2O{{H}^{-}}}}\,\] Or \[{{K}_{sp}}=4{{s}^{3}}\] ?(iii) From Eqs. (ii) and (iii), we get \[s=\sqrt[3]{\frac{12\times {{10}^{-12}}}{4}}=1.44\times {{10}^{-4}}\] \[\therefore \] \[\theta ={{45}^{o}}\]You need to login to perform this action.
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