A) 2/5
B) 2/7
C) 3/5
D) 3/7
Correct Answer: B
Solution :
Total energy \[v=\frac{dx}{dt}=2t-6\] \[t=0\] \[u=-6\,\,m{{s}^{-1}}\] \[t=6\] Now, rotational kinetic energy \[v=6\,m{{s}^{-1}}\] \[W=\frac{1}{2}m{{v}^{2}}-\frac{1}{2}m{{u}^{2}}\Rightarrow \,W=0\]
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