A) 12.5%
B) 25%
C) 50%
D) None of these
Correct Answer: A
Solution :
Oxygen forms fee structure in which \[\theta ={{45}^{o}}\] occupies tetrahedral voids and \[K={{K}_{R}}+{{K}_{T}}=\frac{1}{2}I{{\omega }^{2}}+\frac{1}{2}m{{v}^{2}}\] ions occupies octahedral void per unit cell. Total number of tetrahedral voids \[=\frac{1}{2}\,\left[ \frac{2}{5}\,m{{r}^{2}} \right]{{\omega }^{2}}+\frac{1}{2}\,m{{r}^{2}}{{\omega }^{2}}\] \[=\frac{1}{5}m{{r}^{2}}{{\omega }^{2}}+\frac{1}{2}m{{r}^{2}}{{\omega }^{2}}\] % tetrahedral void occupied \[=\frac{7}{10}m{{r}^{2}}{{\omega }^{2}}\] = 12. 5%
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