JEE Main & Advanced Sample Paper JEE Main Sample Paper-13

  • question_answer
    Direction (Q. Nos. 54): A solution of sucrose [M (mass) = 342] has been prepared In dissolving 68.4 g of sucrose in 1 kg of water. \[{{K}_{f}}\] for water is \[1.\,86\,kg\,\,mo{{l}^{-1}}\] and vapour pressure of water at 298 K is 0.024 atm. Assume density of the solution is 1 g/mL.
    The freezing point of the solution will be

    A)  \[\text{ }0.684{}^\circ C\]           

    B)  \[\text{ }0.342{}^\circ C\]

    C)  \[\text{ }0.372{}^\circ C\]

    D)  \[\text{ }0.186{}^\circ C\]

    Correct Answer: C

    Solution :

            \[=-12t+5\] \[t=0.25\,s,\] = 0.372 \[E=-12\times 0.25+5=-3+5=2V\] Freezing point of aqueous solution \[\therefore \]


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