A) \[{{30}^{o}}\]
B) \[{{45}^{o}}\]
C) \[{{60}^{o}}\]
D) \[{{75}^{o}}\]
Correct Answer: B
Solution :
Let, F be the KE at the instant of projection, then \[=(2mv)\] As KE at topmost point = PE at topmost point \[=(2mv)\,(nt)\] KE at topmost point, \[({{d}_{d}}g)t=2mv\times nt\] But \[\Rightarrow \] \[10\times 9.8=2\times 5\times v\times 10\] \[v=\frac{98}{100}=0.98\,m/s\] \[x={{(t-3)}^{2}}={{t}^{2}}-6t+9\] \[\Rightarrow \]You need to login to perform this action.
You will be redirected in
3 sec