A) \[\frac{mgR}{6}\]
B) \[\frac{mgR}{3}\]
C) \[\frac{2mgR}{3}\]
D) \[\frac{5}{6}\,mgR\]
Correct Answer: D
Solution :
Total initial energy \[\therefore \] Total final energy \[{{K}_{a}}=\frac{[HCO{{O}^{-}}]\,[{{H}^{+}}]}{[HCOOH]}\] So. \[[{{K}_{a}}=\] \[(-3.7)=1.995\times {{10}^{-4}}]\] (\[\because \] height = 2R) Energy required \[x=\frac{1.995\times {{10}^{-4}}\times 0.15}{0.1}\] \[[HCO{{O}^{-}}]=2.99\times {{10}^{-4}}\] \[\therefore \] \[=\frac{2.99\times {{10}^{-4}}}{0.15}\times 100\] \[I=\frac{pV}{RT}=\frac{5\times 9}{RT}\]You need to login to perform this action.
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