A) \[B{{a}^{2+}}\]
B) \[F{{e}^{2+}}\]
C) \[M{{g}^{2+}}\]
D) \[P{{b}^{2+}}\]
Correct Answer: D
Solution :
\[{{q}_{1}}\,:\,\,{{q}_{2}}=1:\,9,\,\,L=1\,m\] \[x\] \[\therefore \] \[\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{1}{{{x}^{2}}}=\frac{1}{4\pi {{\varepsilon }_{0}}}\,\frac{9}{{{(1-x)}^{2}}}\]You need to login to perform this action.
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