A) 16170
B) 13300
C) 16100
D) None of these
Correct Answer: A
Solution :
\[\frac{0.024-{{p}_{S}}}{{{p}_{S}}}=\frac{68.4}{342}\times \frac{18}{1000}\] \[\therefore \] \[{{p}_{S}}=0.0239\,atm\] \[\Delta {{T}_{f}}={{K}_{f}}m\]You need to login to perform this action.
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