A) \[Kl+HCl\]
B) \[{{O}_{3}}\]
C) \[PbS\]
D) \[N{{a}_{2}}S{{O}_{3}}\]
Correct Answer: B
Solution :
\[{{O}_{3}}\] is more powerful oxidising agent than \[{{H}_{2}}{{O}_{2}}\], So, \[{{H}_{2}}{{O}_{2}}\] reduces \[{{O}_{3}}\] to \[{{O}_{2}}\] \[{{O}_{3}}+{{H}_{2}}{{O}_{2}}\xrightarrow{\,}\,{{H}_{2}}O+2{{O}_{2}}\]
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