A) \[fof\,\,(2)=2\]
B) \[fof\,\,(2)=1\]
C) \[f({{S}_{n}})\] is divisible by 9
D) \[fof\,(5)=1\]
Correct Answer: B
Solution :
Given relation \[f(n)=f(n-1)+f(n-2)\] \[f(2)=f(1)+f(0)=1+0=1\] \[f(3)=f(2)+f(1)=1+1=2\] \[f(4)=f(3)+f(2)=2+1=3\] \[f(5)=f(4)+f(3)=3+2=5\] \[\therefore \] \[fof(1)=f\{f(1)\}=f(1)=1\] \[fof(2)=f\{f(2)\}=f(1)=1\]You need to login to perform this action.
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