A) The charge on outer surface of shell is uniformly distributed.
B) The charge on outer surface of shell is non-uniformly distributed.
C) The nature of distribution of charge on outer surface of shell cannot be predicted from the given information.
D) None of the above
Correct Answer: B
Solution :
To solve this question we have to use the concept that "the resultant electric field at any point inside a conducting shell due to ail outside charges is zero," and that "E at any internal point due to uniformly charged conducting spherical shell is zero." Consider any point P inside the shell, at P, the resultant electric field due to I, II and charge on outer surface of shell must be zero. \[{{E}_{p}}={{E}_{I}}+{{E}_{II}}+{{E}_{\text{outer}\,\text{surface}\ \text{charge}}}=0\] But \[{{E}_{I}}+{{E}_{II}}\ne 0,\] so \[{{E}_{\text{outer}\,\text{surface}\,\text{charge}}}\ne 0\], it means charge distribution is outer surface of shell is non-uniform.You need to login to perform this action.
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