A) (0, 1)
B) (1, 2)
C) (2, 3)
D) (- 1, 0)
Correct Answer: B
Solution :
\[\frac{1}{{{\log }_{1/3}}\frac{1}{5}}+\frac{1}{{{\log }_{1/4}}\frac{1}{5}}\] \[={{\log }_{1/5}}\frac{1}{3}+{{\log }_{1/5}}\frac{1}{4}\] \[={{\log }_{5}}3+{{\log }_{5}}4={{\log }_{5}}12\] \[\because \] \[5<12<{{5}^{2}}\] So, \[{{\log }_{5}}\,12\,\in \,(1,2)\]You need to login to perform this action.
You will be redirected in
3 sec