A) \[{{t}_{1}}={{t}_{2}}\]
B) \[{{t}_{1}}<{{t}_{2}}\]
C) \[{{t}_{1}}>{{t}_{2}}\]
D) cannot be predicted
Correct Answer: C
Solution :
Path AB \[a=0\], vel. = constant = V Path A'B' \[{{a}_{x}}=N\sin \theta \] So, vel. increases up till lowest point. By W.E.T, \[{{W}_{g}}\] from A' to B' is 0 so \[{{\text{V}}_{\text{f}}}\text{=V}\] From lowest point till B', \[{{a}_{x}}=-N\sin \theta \] Sol vel. decreases up till B' but is always greater than V. Hence, \[{{V}_{A'B'}}>V\]for whole path. \[\therefore \,\,{{t}_{2}}<{{t}_{1}}\]You need to login to perform this action.
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