JEE Main & Advanced Sample Paper JEE Main Sample Paper-15

  • question_answer
    A line of charge with linear charge density X extends along the z-axis from \[z=-h\] to \[z=+h\]. The distance of the point on the y-axis where electric field has magnitude \[\frac{\lambda }{\sqrt{8}\pi {{\in }_{0}}h},\]is                                          

    A)  h from the wire              

    B)  \[\sqrt{2}\]h from the wire

    C)  2h from the wire

    D)  3h from the wire.

    Correct Answer: A

    Solution :

    \[E=\frac{\lambda }{2\pi {{\varepsilon }_{0}}y}\sin \theta =\frac{\lambda }{2\sqrt{2}\pi {{\varepsilon }_{0}}h}\therefore y=h\]


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