JEE Main & Advanced
Sample Paper
JEE Main Sample Paper-15
question_answer
In a resonance tube water is filled so that height of air column is 0.1 m when it resonates in its fundamental mode. Now water is removed so that the height of air column becomes 0.35 m and it resonates with next higher frequency. Then end correction is
A) 0.012
B) 0.025
C) 0.05
D) 0.24
Correct Answer:
B
Solution :
End correction \[=\frac{{{L}_{2}}-3{{L}_{1}}}{2}=0.025\]