A) h from the wire
B) \[\sqrt{2}\]h from the wire
C) 2h from the wire
D) 3h from the wire.
Correct Answer: A
Solution :
\[E=\frac{\lambda }{2\pi {{\varepsilon }_{0}}y}\sin \theta =\frac{\lambda }{2\sqrt{2}\pi {{\varepsilon }_{0}}h}\therefore y=h\]You need to login to perform this action.
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