A) zero
B)
C) \[\Delta \phi =\frac{\Delta g}{{{g}_{0}}\beta \cos (2\phi )}\]
D) \[\Delta \phi =\frac{\Delta g}{{{g}_{0}}}\]
Correct Answer: B
Solution :
\[dg={{g}_{0}}[0+n\sin 2\phi \,d\phi ]\] \[d\phi =\frac{dg}{{{g}_{0}}\beta \sin 2\phi }\]You need to login to perform this action.
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