A) 150
B) 500
C) 50
D) 250
Correct Answer: A
Solution :
Current amplification factor\[\beta =\frac{\Delta {{I}_{C}}}{\Delta {{I}_{B}}}\] \[=\frac{(8\cdot 5-2\cdot 5)mA}{(50-10)\mu A}=\frac{6\cdot 0\times {{10}^{-3}}}{40\times {{10}^{-6}}}=150\]You need to login to perform this action.
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