A) \[{{x}^{2}}+{{y}^{2}}-4x-396=0\]
B) \[{{x}^{2}}+{{y}^{2}}-4x-360=0\]
C) \[{{x}^{2}}+{{y}^{2}}-4x-346=0\]
D) \[{{x}^{2}}+{{y}^{2}}-4x-300=0\]
Correct Answer: A
Solution :
We know \[PS=QS=SR\] Hence, S is circumventer of \[\Delta PQR\] Equation of required circle \[{{(x-2)}^{2}}+{{(y-0)}^{2}}={{(2-18)}^{2}}+{{(-12)}^{2}}\] \[{{x}^{2}}+{{y}^{2}}-4x-396=0\]You need to login to perform this action.
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