A) 0
B) e
C) \[{{e}^{2}}\]
D) 1
Correct Answer: A
Solution :
\[\underset{x\to \infty }{\mathop{\lim }}\,\frac{2{{\left( \int\limits_{0}^{x}{{{e}^{{{t}^{2}}}}dt} \right)}^{2}}.{{e}^{{{x}^{2}}}}}{{{e}^{2{{x}^{2}}}}}\] \[\underset{x\to \infty }{\mathop{\text{L}im}}\,\frac{2\int\limits_{0}^{x}{{{e}^{{{t}^{2}}}}dt}}{{{e}^{{{x}^{2}}}}}=\underset{x\to \infty }{\mathop{\text{L}im}}\,\frac{2{{e}^{{{x}^{2}}}}}{2x{{e}^{{{x}^{2}}}}}=0\]You need to login to perform this action.
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