A) 1
B) 2
C) \[\frac{1}{2}\]
D) \[\frac{1}{4}\]
Correct Answer: B
Solution :
\[\frac{z+2i}{z-2i}=\lambda i\Rightarrow \frac{2z}{4i}=\frac{\lambda i+1}{\lambda i-1}\] \[\frac{z}{2i}=\frac{\lambda i+1}{\lambda i-1}\Rightarrow |z|=2\]You need to login to perform this action.
You will be redirected in
3 sec